(1/3)^(3x+6)=9x-1

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Solution for (1/3)^(3x+6)=9x-1 equation: 



(1/3)^(3x+6)=9x-1

We move all terms to the left:

(1/3)^(3x+6)-(9x-1)=0



Domain of the equation: 3)^(3x+6)!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^(3x+6)-(9x-1)=0

We get rid of parentheses

(+1/3)^(3x+6)-9x+1=0

We multiply all the terms by the denominator


(+1-9x*3)^(3x+6)+1*3)^(3x+6)=0

We add all the numbers together, and all the variables

(-9x*3+1)^(3x+6)+1*3)^(3x+6)=0

We add all the numbers together, and all the variables

(-9x*3+1)^(3x+6)+1*3)^(3x=0

Wy multiply elements

(-9x*3+1)^(3x+6)+3x=0

We add all the numbers together, and all the variables

3x+(-9x*3+1)^(3x+6)=0

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